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-0.08x^2-40x+400000=0
a = -0.08; b = -40; c = +400000;
Δ = b2-4ac
Δ = -402-4·(-0.08)·400000
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{129600}=360$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-360}{2*-0.08}=\frac{-320}{-0.16} =+2000 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+360}{2*-0.08}=\frac{400}{-0.16} =-2500 $
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